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For
those of you daunted by the questions set in our Christmas quiz but
interested on some of the theory behind the questions here is a
summary.
Questions
1 and 2. If you attended an
Institute
of
Vehicle Recovery
course you would have been taught that on arrival at the recovery
scene an assessment of the job should be done and that maybe these
factors should be taken into consideration.
ROLLING
RESISTANCE
GRADIENT
RESISTANCE
DAMAGE
RESISTANCE
Various
organizations have developed factors that when applied to the weight
of the casualty aid the operator to estimate how much pull is
required.
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Q1
YOU ARE CALLED TO WINCH A TIPPER,
WHICH IS UNDAMAGED, OFF A BUILDING SITE, THE GROUND IS LEVEL AND SOFT
CLAY, THE TRUCK WEIGHS 24 TONNES, HOW MUCH WINCHING POWER WILL YOU
NEED?
A1 In
question 1, we know that the ground is level and that the truck which
weighs 24 tonnes is undamaged, so we can forget GRADIENT and DAMAGE
RESISTANCE. The only two things we need to consider is the 24
tonnes weight and the fact that this is stuck on soft clay, the
recognized factor for this type of ground is a dividing factor of 2.
The answer then is 24 divided by 2 = 12 tonnes |
Q2
THE NEXT JOB YOU GET IS TO RECOVER
A TRACTOR/TRAILER, WITH ALL ITS WHEELS INTACT AND WEIGHING 44 TONNES,
UP A MOTORWAY EMBANKMENT THE SLOPE IS 20 DEGREES AND HAS A SURFACE OF
SOFT GRASS, HOW MUCH WINCHING POWER DO YOU NEED TO PULL THE CASUALTY
UP THE SLOPE?
A2
In question 2, we know the casualty weighs 44 tonnes and in this
instance it is also undamaged, so we can disregard DAMAGE RESISTANCE,
however we have a slope to pull it up of 20 degrees and the surface is
soft grass. The calculation for the winching effort to overcome the
GRADIENT RESISTANCE is WEIGHT OF CASUALTY DIVIDED BY 60 MULTIPLIED BY
THE SLOPE IN DEGREES hence 44 tonnes divided by 60 multiplied by the
20 degree slope equals 14.6 tonnes, you have to add to this the fact
that the truck sits on soft grass, it is more difficult to pull
something over soft grass than hard standing. The factor to use for
soft grass is 4, hence 44 divided by 4 equals 11 tonnes, this must be
added to the GRADIENT RESISTANCE, so the total winching effort
required is 14.6 + 11, the answer being 25.6 tonnes.
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